Base | Representation |
---|---|
bin | 1100110110001011101110… |
… | …1011001100100011100101 |
3 | 1212000100002121121101222202 |
4 | 3031202323223030203211 |
5 | 3322411000242213021 |
6 | 50012534055104245 |
7 | 2655332460424355 |
oct | 315427353144345 |
9 | 55010077541882 |
10 | 14125001132261 |
11 | 45564199a0468 |
12 | 170162a372085 |
13 | 7b5c9c2a5376 |
14 | 36b921a8cb65 |
15 | 197654e80a0b |
hex | cd8bbacc8e5 |
14125001132261 has 2 divisors, whose sum is σ = 14125001132262. Its totient is φ = 14125001132260.
The previous prime is 14125001132251. The next prime is 14125001132279. The reversal of 14125001132261 is 16223110052141.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14080273112161 + 44728020100 = 3752369^2 + 211490^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14125001132261 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14125001132251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062500566130 + 7062500566131.
It is an arithmetic number, because the mean of its divisors is an integer number (7062500566131).
Almost surely, 214125001132261 is an apocalyptic number.
It is an amenable number.
14125001132261 is a deficient number, since it is larger than the sum of its proper divisors (1).
14125001132261 is an equidigital number, since it uses as much as digits as its factorization.
14125001132261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 29.
The spelling of 14125001132261 in words is "fourteen trillion, one hundred twenty-five billion, one million, one hundred thirty-two thousand, two hundred sixty-one".
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