14125001132293 has 2 divisors, whose sum is σ = 14125001132294. Its totient is φ = 14125001132292.

The previous prime is 14125001132279. The next prime is 14125001132317. The reversal of 14125001132293 is 39223110052141.

14125001132293 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12377681985249 + 1747319147044 = 3518193^2 + 1321862^2 .

It is a cyclic number.

It is not a de Polignac number, because 14125001132293 - 2⁵ = 14125001132261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14125001133293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062500566146 + 7062500566147.

It is an arithmetic number, because the mean of its divisors is an integer number (7062500566147).

Almost surely, 2^{14125001132293} is an apocalyptic number.

It is an amenable number.

14125001132293 is a deficient number, since it is larger than the sum of its proper divisors (1).

14125001132293 is an equidigital number, since it uses as much as digits as its factorization.

14125001132293 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 34.

The spelling of 14125001132293 in words is "fourteen trillion, one hundred twenty-five billion, one million, one hundred thirty-two thousand, two hundred ninety-three".