14125005313535 has 4 divisors (see below), whose sum is σ = 16950006376248. Its totient is φ = 11300004250824.

The previous prime is 14125005313511. The next prime is 14125005313571. The reversal of 14125005313535 is 53531350052141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14125005313535 - 2¹⁰ = 14125005312511 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1412500531349 + ... + 1412500531358.

It is an arithmetic number, because the mean of its divisors is an integer number (4237501594062).

Almost surely, 2^{14125005313535} is an apocalyptic number.

14125005313535 is a deficient number, since it is larger than the sum of its proper divisors (2825001062713).

14125005313535 is an equidigital number, since it uses as much as digits as its factorization.

14125005313535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2825001062712.

The product of its (nonzero) digits is 135000, while the sum is 38.

Adding to 14125005313535 its reverse (53531350052141), we get a palindrome (67656355365676).

The spelling of 14125005313535 in words is "fourteen trillion, one hundred twenty-five billion, five million, three hundred thirteen thousand, five hundred thirty-five".