Base | Representation |
---|---|
bin | 11010010011110101… |
… | …10000111010001101 |
3 | 1100110101202112210101 |
4 | 31021322300322031 |
5 | 212412002341331 |
6 | 10253340411101 |
7 | 1010013613243 |
oct | 151172607215 |
9 | 40411675711 |
10 | 14125043341 |
11 | 5a99245142 |
12 | 28a2546a91 |
13 | 14414b0516 |
14 | 97dd46793 |
15 | 57a0d3061 |
hex | 349eb0e8d |
14125043341 has 2 divisors, whose sum is σ = 14125043342. Its totient is φ = 14125043340.
The previous prime is 14125043269. The next prime is 14125043407. The reversal of 14125043341 is 14334052141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13972422025 + 152621316 = 118205^2 + 12354^2 .
It is an emirp because it is prime and its reverse (14334052141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14125043341 - 227 = 13990825613 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14125043041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062521670 + 7062521671.
It is an arithmetic number, because the mean of its divisors is an integer number (7062521671).
Almost surely, 214125043341 is an apocalyptic number.
It is an amenable number.
14125043341 is a deficient number, since it is larger than the sum of its proper divisors (1).
14125043341 is an equidigital number, since it uses as much as digits as its factorization.
14125043341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 14125043341 its reverse (14334052141), we get a palindrome (28459095482).
The spelling of 14125043341 in words is "fourteen billion, one hundred twenty-five million, forty-three thousand, three hundred forty-one".
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