Base | Representation |
---|---|
bin | 11010010011110101… |
… | …10000111011001111 |
3 | 1100110101202112212211 |
4 | 31021322300323033 |
5 | 212412002342112 |
6 | 10253340411251 |
7 | 1010013613366 |
oct | 151172607317 |
9 | 40411675784 |
10 | 14125043407 |
11 | 5a992451a2 |
12 | 28a2546b27 |
13 | 14414b0567 |
14 | 97dd467dd |
15 | 57a0d30a7 |
hex | 349eb0ecf |
14125043407 has 2 divisors, whose sum is σ = 14125043408. Its totient is φ = 14125043406.
The previous prime is 14125043341. The next prime is 14125043411. The reversal of 14125043407 is 70434052141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14125043407 - 215 = 14125010639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14125040407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7062521703 + 7062521704.
It is an arithmetic number, because the mean of its divisors is an integer number (7062521704).
Almost surely, 214125043407 is an apocalyptic number.
14125043407 is a deficient number, since it is larger than the sum of its proper divisors (1).
14125043407 is an equidigital number, since it uses as much as digits as its factorization.
14125043407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 14125043407 its reverse (70434052141), we get a palindrome (84559095548).
The spelling of 14125043407 in words is "fourteen billion, one hundred twenty-five million, forty-three thousand, four hundred seven".
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