14125405003 has 4 divisors (see below), whose sum is σ = 14132997088. Its totient is φ = 14117812920.

The previous prime is 14125405001. The next prime is 14125405039. The reversal of 14125405003 is 30050452141.

It is a happy number.

14125405003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14125405003 - 2¹ = 14125405001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14125405001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3793251 + ... + 3796972.

It is an arithmetic number, because the mean of its divisors is an integer number (3533249272).

Almost surely, 2^14125405003 is an apocalyptic number.

14125405003 is a deficient number, since it is larger than the sum of its proper divisors (7592085).

14125405003 is an equidigital number, since it uses as much as digits as its factorization.

14125405003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7592084.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 14125405003 its reverse (30050452141), we get a palindrome (44175857144).

The spelling of 14125405003 in words is "fourteen billion, one hundred twenty-five million, four hundred five thousand, three".