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1412541030 = 23547084701
BaseRepresentation
bin101010000110001…
…1010101001100110
310122102221112000110
41110030122221212
510343102303110
6352055353450
750001254265
oct12414325146
93572845013
101412541030
11665384a8a
12335082886
1319684cac4
14d58585dc
1584020a20
hex5431aa66

1412541030 has 16 divisors (see below), whose sum is σ = 3390098544. Its totient is φ = 376677600.

The previous prime is 1412540963. The next prime is 1412541037. The reversal of 1412541030 is 301452141.

It is a super-2 number, since 2×14125410302 = 3990544322866921800, which contains 22 as substring.

It is an alternating number because its digits alternate between odd and even.

It is a junction number, because it is equal to n+sod(n) for n = 1412540988 and 1412541006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412541037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23542321 + ... + 23542380.

It is an arithmetic number, because the mean of its divisors is an integer number (211881159).

Almost surely, 21412541030 is an apocalyptic number.

1412541030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1412541030 is an abundant number, since it is smaller than the sum of its proper divisors (1977557514).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1412541030 is a wasteful number, since it uses less digits than its factorization.

1412541030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47084711.

The product of its (nonzero) digits is 480, while the sum is 21.

The square root of 1412541030 is about 37583.7867969687. The cubic root of 1412541030 is about 1122.0193771457.

Adding to 1412541030 its reverse (301452141), we get a palindrome (1713993171).

Subtracting from 1412541030 its reverse (301452141), we obtain a square (1111088889 = 333332).

It can be divided in two parts, 14125 and 41030, that added together give a palindrome (55155).

The spelling of 1412541030 in words is "one billion, four hundred twelve million, five hundred forty-one thousand, thirty".

Divisors: 1 2 3 5 6 10 15 30 47084701 94169402 141254103 235423505 282508206 470847010 706270515 1412541030