Base | Representation |
---|---|
bin | 10100100011100010101… |
… | …010010101001000010111 |
3 | 12000001001011211111121010 |
4 | 110203202222111020113 |
5 | 141120401304124003 |
6 | 3000530100023303 |
7 | 204024233032011 |
oct | 24434252251027 |
9 | 5001034744533 |
10 | 1412552020503 |
11 | 4a5072877058 |
12 | 1a9918991b33 |
13 | a3284238740 |
14 | 4c5216811b1 |
15 | 26b250c2003 |
hex | 148e2a95217 |
1412552020503 has 16 divisors (see below), whose sum is σ = 2028301140096. Its totient is φ = 869253646560.
The previous prime is 1412552020489. The next prime is 1412552020507. The reversal of 1412552020503 is 3050202552141.
It is not a de Polignac number, because 1412552020503 - 210 = 1412552019479 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1412552020507) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7270876 + ... + 7462622.
It is an arithmetic number, because the mean of its divisors is an integer number (126768821256).
Almost surely, 21412552020503 is an apocalyptic number.
1412552020503 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1412552020503 is a deficient number, since it is larger than the sum of its proper divisors (615749119593).
1412552020503 is a wasteful number, since it uses less digits than its factorization.
1412552020503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 380654.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 1412552020503 its reverse (3050202552141), we get a palindrome (4462754572644).
The spelling of 1412552020503 in words is "one trillion, four hundred twelve billion, five hundred fifty-two million, twenty thousand, five hundred three".
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