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14128407303 = 319853237217
BaseRepresentation
bin11010010100001111…
…00110001100000111
31100110122002110021120
431022013212030013
5212413333013203
610253540445023
71010054323563
oct151207461407
940418073246
1014128407303
115aa013257a
1228a36a9773
1314420ba72a
149805806a3
1557a549b53
hex34a1e6307

14128407303 has 8 divisors (see below), whose sum is σ = 18838904688. Its totient is φ = 9418424064.

The previous prime is 14128407287. The next prime is 14128407347. The reversal of 14128407303 is 30370482141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14128407303 - 24 = 14128407287 is a prime.

It is a super-2 number, since 2×141284073032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14128407373) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59050 + ... + 178167.

It is an arithmetic number, because the mean of its divisors is an integer number (2354863086).

Almost surely, 214128407303 is an apocalyptic number.

14128407303 is a deficient number, since it is larger than the sum of its proper divisors (4710497385).

14128407303 is a wasteful number, since it uses less digits than its factorization.

14128407303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 257073.

The product of its (nonzero) digits is 16128, while the sum is 33.

Adding to 14128407303 its reverse (30370482141), we get a palindrome (44498889444).

The spelling of 14128407303 in words is "fourteen billion, one hundred twenty-eight million, four hundred seven thousand, three hundred three".

Divisors: 1 3 19853 59559 237217 711651 4709469101 14128407303