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1412844911293 is a prime number
BaseRepresentation
bin10100100011110100000…
…111100111101010111101
312000001210120221220020011
4110203310013213222331
5141122001244130133
63001015121423221
7204034420412014
oct24436407475275
95001716856204
101412844911293
114a5203135262
121a999aa9ab11
13a32ccb176ba
144c54c523a7b
1526b40b796cd
hex148f41e7abd

1412844911293 has 2 divisors, whose sum is σ = 1412844911294. Its totient is φ = 1412844911292.

The previous prime is 1412844911273. The next prime is 1412844911297. The reversal of 1412844911293 is 3921194482141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 807269904324 + 605575006969 = 898482^2 + 778187^2 .

It is a cyclic number.

It is not a de Polignac number, because 1412844911293 - 29 = 1412844910781 is a prime.

It is a super-2 number, since 2×14128449112932 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1412844911297) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706422455646 + 706422455647.

It is an arithmetic number, because the mean of its divisors is an integer number (706422455647).

Almost surely, 21412844911293 is an apocalyptic number.

It is an amenable number.

1412844911293 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412844911293 is an equidigital number, since it uses as much as digits as its factorization.

1412844911293 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 497664, while the sum is 49.

The spelling of 1412844911293 in words is "one trillion, four hundred twelve billion, eight hundred forty-four million, nine hundred eleven thousand, two hundred ninety-three".