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1412844911341 is a prime number
BaseRepresentation
bin10100100011110100000…
…111100111101011101101
312000001210120221220021221
4110203310013213223231
5141122001244130331
63001015121423341
7204034420412113
oct24436407475355
95001716856257
101412844911341
114a52031352a6
121a999aa9ab51
13a32ccb17726
144c54c523ab3
1526b40b79711
hex148f41e7aed

1412844911341 has 2 divisors, whose sum is σ = 1412844911342. Its totient is φ = 1412844911340.

The previous prime is 1412844911297. The next prime is 1412844911411. The reversal of 1412844911341 is 1431194482141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 871375575625 + 541469335716 = 933475^2 + 735846^2 .

It is a cyclic number.

It is not a de Polignac number, because 1412844911341 - 211 = 1412844909293 is a prime.

It is a super-2 number, since 2×14128449113412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1412844911041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706422455670 + 706422455671.

It is an arithmetic number, because the mean of its divisors is an integer number (706422455671).

Almost surely, 21412844911341 is an apocalyptic number.

It is an amenable number.

1412844911341 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412844911341 is an equidigital number, since it uses as much as digits as its factorization.

1412844911341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 110592, while the sum is 43.

The spelling of 1412844911341 in words is "one trillion, four hundred twelve billion, eight hundred forty-four million, nine hundred eleven thousand, three hundred forty-one".