14130011113201 has 4 divisors (see below), whose sum is σ = 14329025354304. Its totient is φ = 13930996872100.

The previous prime is 14130011113177. The next prime is 14130011113217. The reversal of 14130011113201 is 10231111003141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14130011113201 - 2²⁵ = 14129977558769 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14130011113271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99507120445 + ... + 99507120586.

It is an arithmetic number, because the mean of its divisors is an integer number (3582256338576).

Almost surely, 2^{14130011113201} is an apocalyptic number.

It is an amenable number.

14130011113201 is a deficient number, since it is larger than the sum of its proper divisors (199014241103).

14130011113201 is an equidigital number, since it uses as much as digits as its factorization.

14130011113201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 199014241102.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 14130011113201 its reverse (10231111003141), we get a palindrome (24361122116342).

The spelling of 14130011113201 in words is "fourteen trillion, one hundred thirty billion, eleven million, one hundred thirteen thousand, two hundred one".