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14130033532 = 2223153587321
BaseRepresentation
bin11010010100011011…
…10011001101111100
31100110202011002001021
431022031303031330
5212414242033112
610254035353524
71010104206016
oct151215631574
940422132037
1014130033532
115aa104336a
1228a41528a4
1314425399b4
149808851b6
1557a76b907
hex34a37337c

14130033532 has 12 divisors (see below), whose sum is σ = 25802670096. Its totient is φ = 6757842080.

The previous prime is 14130033527. The next prime is 14130033539. The reversal of 14130033532 is 23533003141.

It is a junction number, because it is equal to n+sod(n) for n = 14130033497 and 14130033506.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14130033539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76793569 + ... + 76793752.

It is an arithmetic number, because the mean of its divisors is an integer number (2150222508).

Almost surely, 214130033532 is an apocalyptic number.

It is an amenable number.

14130033532 is a deficient number, since it is larger than the sum of its proper divisors (11672636564).

14130033532 is a wasteful number, since it uses less digits than its factorization.

14130033532 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153587348 (or 153587346 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 25.

Adding to 14130033532 its reverse (23533003141), we get a palindrome (37663036673).

The spelling of 14130033532 in words is "fourteen billion, one hundred thirty million, thirty-three thousand, five hundred thirty-two".

Divisors: 1 2 4 23 46 92 153587321 307174642 614349284 3532508383 7065016766 14130033532