Base | Representation |
---|---|
bin | 1100110110011110110100… |
… | …0001011001001011100111 |
3 | 1212000211022122012011011212 |
4 | 3031213231001121023213 |
5 | 3323001443221031043 |
6 | 50015142300022035 |
7 | 2655603434204621 |
oct | 315475501311347 |
9 | 55024278164155 |
10 | 14130124002023 |
11 | 455860869a327 |
12 | 1702619b3191b |
13 | 7b6607724153 |
14 | 36bc8a1b5c11 |
15 | 197854aa8018 |
hex | cd9ed0592e7 |
14130124002023 has 2 divisors, whose sum is σ = 14130124002024. Its totient is φ = 14130124002022.
The previous prime is 14130124001963. The next prime is 14130124002037. The reversal of 14130124002023 is 32020042103141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14130124002023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14130124002023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14130124004023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065062001011 + 7065062001012.
It is an arithmetic number, because the mean of its divisors is an integer number (7065062001012).
Almost surely, 214130124002023 is an apocalyptic number.
14130124002023 is a deficient number, since it is larger than the sum of its proper divisors (1).
14130124002023 is an equidigital number, since it uses as much as digits as its factorization.
14130124002023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14130124002023 its reverse (32020042103141), we get a palindrome (46150166105164).
The spelling of 14130124002023 in words is "fourteen trillion, one hundred thirty billion, one hundred twenty-four million, two thousand, twenty-three".
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