1413112142433 has 4 divisors (see below), whose sum is σ = 1884149523248. Its totient is φ = 942074761620.

The previous prime is 1413112142381. The next prime is 1413112142437. The reversal of 1413112142433 is 3342412113141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1413112142433 - 2¹⁸ = 1413111880289 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1413112142433.

It is not an unprimeable number, because it can be changed into a prime (1413112142437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235518690403 + ... + 235518690408.

It is an arithmetic number, because the mean of its divisors is an integer number (471037380812).

Almost surely, 2^{1413112142433} is an apocalyptic number.

It is an amenable number.

1413112142433 is a deficient number, since it is larger than the sum of its proper divisors (471037380815).

1413112142433 is an equidigital number, since it uses as much as digits as its factorization.

1413112142433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 471037380814.

The product of its digits is 6912, while the sum is 30.

Adding to 1413112142433 its reverse (3342412113141), we get a palindrome (4755524255574).

The spelling of 1413112142433 in words is "one trillion, four hundred thirteen billion, one hundred twelve million, one hundred forty-two thousand, four hundred thirty-three".