Base | Representation |
---|---|
bin | 10100100100000100000… |
… | …111100111101010111110 |
3 | 12000002111022001211110010 |
4 | 110210010013213222332 |
5 | 141123024004044000 |
6 | 3001101511124050 |
7 | 204044160155460 |
oct | 24440407475276 |
9 | 5002438054403 |
10 | 1413113346750 |
11 | 4a533070a846 |
12 | 1a9a54973626 |
13 | a3343613351 |
14 | 4c57603c130 |
15 | 26b59500d50 |
hex | 149041e7abe |
1413113346750 has 64 divisors (see below), whose sum is σ = 4031006773248. Its totient is φ = 322997335200.
The previous prime is 1413113346739. The next prime is 1413113346763. The reversal of 1413113346750 is 576433113141.
It is a junction number, because it is equal to n+sod(n) for n = 1413113346699 and 1413113346708.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 134576974 + ... + 134587473.
It is an arithmetic number, because the mean of its divisors is an integer number (62984480832).
Almost surely, 21413113346750 is an apocalyptic number.
1413113346750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1413113346750 is an abundant number, since it is smaller than the sum of its proper divisors (2617893426498).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1413113346750 is a wasteful number, since it uses less digits than its factorization.
1413113346750 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 269164474 (or 269164464 counting only the distinct ones).
The product of its (nonzero) digits is 90720, while the sum is 39.
Adding to 1413113346750 its reverse (576433113141), we get a palindrome (1989546459891).
The spelling of 1413113346750 in words is "one trillion, four hundred thirteen billion, one hundred thirteen million, three hundred forty-six thousand, seven hundred fifty".
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