Base | Representation |
---|---|
bin | 1000001110011011011… |
… | …0100000000001100111 |
3 | 111111202021110101112121 |
4 | 2003212312200001213 |
5 | 4303401333000403 |
6 | 144530130330411 |
7 | 13131562116331 |
oct | 2034666400147 |
9 | 444667411477 |
10 | 141312000103 |
11 | 54a25a3824a |
12 | 23479129a07 |
13 | 1043063c011 |
14 | 6ba7994451 |
15 | 3a20ed23bd |
hex | 20e6da0067 |
141312000103 has 2 divisors, whose sum is σ = 141312000104. Its totient is φ = 141312000102.
The previous prime is 141312000073. The next prime is 141312000113. The reversal of 141312000103 is 301000213141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141312000103 - 237 = 3873046631 is a prime.
It is a super-2 number, since 2×1413120001032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141312000113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70656000051 + 70656000052.
It is an arithmetic number, because the mean of its divisors is an integer number (70656000052).
Almost surely, 2141312000103 is an apocalyptic number.
141312000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
141312000103 is an equidigital number, since it uses as much as digits as its factorization.
141312000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 141312000103 its reverse (301000213141), we get a palindrome (442312213244).
The spelling of 141312000103 in words is "one hundred forty-one billion, three hundred twelve million, one hundred three", and thus it is an aban number.
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