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141312113 is a prime number
BaseRepresentation
bin10000110110001…
…00000001110001
3100211220101202222
420123010001301
5242133441423
622004450425
73334063445
oct1033040161
9324811688
10141312113
1172848978
123b3a9a15
1323379647
1414aa6825
15c6153c8
hex86c4071

141312113 has 2 divisors, whose sum is σ = 141312114. Its totient is φ = 141312112.

The previous prime is 141312103. The next prime is 141312121. The reversal of 141312113 is 311213141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 122589184 + 18722929 = 11072^2 + 4327^2 .

It is a cyclic number.

It is not a de Polignac number, because 141312113 - 24 = 141312097 is a prime.

It is a super-2 number, since 2×1413121132 = 39938226561049538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141312091 and 141312100.

It is not a weakly prime, because it can be changed into another prime (141312103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70656056 + 70656057.

It is an arithmetic number, because the mean of its divisors is an integer number (70656057).

Almost surely, 2141312113 is an apocalyptic number.

It is an amenable number.

141312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

141312113 is an equidigital number, since it uses as much as digits as its factorization.

141312113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72, while the sum is 17.

The square root of 141312113 is about 11887.4771503461. The cubic root of 141312113 is about 520.8665445588.

Adding to 141312113 its reverse (311213141), we get a palindrome (452525254).

The spelling of 141312113 in words is "one hundred forty-one million, three hundred twelve thousand, one hundred thirteen".