Base | Representation |
---|---|
bin | 1100110110100100001000… |
… | …1100100101101010111101 |
3 | 1212000222000020002210001111 |
4 | 3031221002030211222331 |
5 | 3323012410032001000 |
6 | 50015540144242021 |
7 | 2655654025404061 |
oct | 315510214455275 |
9 | 55028006083044 |
10 | 14131553000125 |
11 | 45591812947a0 |
12 | 1702958610311 |
13 | 7b67a47b6862 |
14 | 36bd83cb5aa1 |
15 | 1978da279cba |
hex | cda42325abd |
14131553000125 has 32 divisors (see below), whose sum is σ = 20252070633600. Its totient is φ = 9736572384000.
The previous prime is 14131553000107. The next prime is 14131553000137. The reversal of 14131553000125 is 52100035513141.
14131553000125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 14131553000125 - 219 = 14131552475837 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 270434220 + ... + 270486469.
It is an arithmetic number, because the mean of its divisors is an integer number (632877207300).
Almost surely, 214131553000125 is an apocalyptic number.
It is an amenable number.
14131553000125 is a deficient number, since it is larger than the sum of its proper divisors (6120517633475).
14131553000125 is a wasteful number, since it uses less digits than its factorization.
14131553000125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 540920734 (or 540920724 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 14131553000125 its reverse (52100035513141), we get a palindrome (66231588513266).
The spelling of 14131553000125 in words is "fourteen trillion, one hundred thirty-one billion, five hundred fifty-three million, one hundred twenty-five", and thus it is an aban number.
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