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14132054233 = 111284732203
BaseRepresentation
bin11010010100101011…
…00000100011011001
31100110212221201221001
431022111200203121
5212420301213413
610254150545001
71010130323203
oct151225404331
940425851831
1014132054233
115aa21a3570
1228a4968161
131442a9668b
14980c4d773
1557aa1a4dd
hex34a5608d9

14132054233 has 4 divisors (see below), whose sum is σ = 15416786448. Its totient is φ = 12847322020.

The previous prime is 14132054201. The next prime is 14132054239. The reversal of 14132054233 is 33245023141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14132054233 - 25 = 14132054201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14132054239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 642366091 + ... + 642366112.

It is an arithmetic number, because the mean of its divisors is an integer number (3854196612).

Almost surely, 214132054233 is an apocalyptic number.

It is an amenable number.

14132054233 is a deficient number, since it is larger than the sum of its proper divisors (1284732215).

14132054233 is a wasteful number, since it uses less digits than its factorization.

14132054233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1284732214.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 14132054233 its reverse (33245023141), we get a palindrome (47377077374).

The spelling of 14132054233 in words is "fourteen billion, one hundred thirty-two million, fifty-four thousand, two hundred thirty-three".

Divisors: 1 11 1284732203 14132054233