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1413210043397 is a prime number
BaseRepresentation
bin10100100100001001111…
…000011111010000000101
312000002202001000112022102
4110210021320133100011
5141123223232342042
63001115243441445
7204046443112055
oct24441170372005
95002661015272
101413210043397
114a5380255429
121a9a81226285
13a335a66b3b9
144c584c0d565
1526b62c51b32
hex14909e1f405

1413210043397 has 2 divisors, whose sum is σ = 1413210043398. Its totient is φ = 1413210043396.

The previous prime is 1413210043391. The next prime is 1413210043457. The reversal of 1413210043397 is 7933400123141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 956388158401 + 456821884996 = 977951^2 + 675886^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1413210043397 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1413210043397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413210043391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706605021698 + 706605021699.

It is an arithmetic number, because the mean of its divisors is an integer number (706605021699).

Almost surely, 21413210043397 is an apocalyptic number.

It is an amenable number.

1413210043397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413210043397 is an equidigital number, since it uses as much as digits as its factorization.

1413210043397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 38.

The spelling of 1413210043397 in words is "one trillion, four hundred thirteen billion, two hundred ten million, forty-three thousand, three hundred ninety-seven".