1413210431231 has 2 divisors, whose sum is σ = 1413210431232. Its totient is φ = 1413210431230.

The previous prime is 1413210431123. The next prime is 1413210431233. The reversal of 1413210431231 is 1321340123141.

Together with previous prime (1413210431123) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1413210431231 is a prime.

It is a super-2 number, since 2×1413210431231² (a number of 25 digits) contains 22 as substring.

Together with 1413210431233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1413210431231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413210431233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706605215615 + 706605215616.

It is an arithmetic number, because the mean of its divisors is an integer number (706605215616).

Almost surely, 2^{1413210431231} is an apocalyptic number.

1413210431231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413210431231 is an equidigital number, since it uses as much as digits as its factorization.

1413210431231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 1413210431231 its reverse (1321340123141), we get a palindrome (2734550554372).

The spelling of 1413210431231 in words is "one trillion, four hundred thirteen billion, two hundred ten million, four hundred thirty-one thousand, two hundred thirty-one".