14132143433 has 2 divisors, whose sum is σ = 14132143434. Its totient is φ = 14132143432.

The previous prime is 14132143429. The next prime is 14132143447. The reversal of 14132143433 is 33434123141.

It is a happy number.

14132143433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9653455504 + 4478687929 = 98252^2 + 66923^2 .

It is an emirp because it is prime and its reverse (33434123141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14132143433 - 2² = 14132143429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14132143396 and 14132143405.

It is not a weakly prime, because it can be changed into another prime (14132143423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066071716 + 7066071717.

It is an arithmetic number, because the mean of its divisors is an integer number (7066071717).

Almost surely, 2^14132143433 is an apocalyptic number.

It is an amenable number.

14132143433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14132143433 is an equidigital number, since it uses as much as digits as its factorization.

14132143433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10368, while the sum is 29.

Adding to 14132143433 its reverse (33434123141), we get a palindrome (47566266574).

The spelling of 14132143433 in words is "fourteen billion, one hundred thirty-two million, one hundred forty-three thousand, four hundred thirty-three".