1413305111341 has 4 divisors (see below), whose sum is σ = 1414598163772. Its totient is φ = 1412012058912.

The previous prime is 1413305111329. The next prime is 1413305111363. The reversal of 1413305111341 is 1431115033141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 650206773316 + 763098338025 = 806354^2 + 873555^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413305111341 - 2¹⁹ = 1413304587053 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413305112341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 646524576 + ... + 646526761.

It is an arithmetic number, because the mean of its divisors is an integer number (353649540943).

Almost surely, 2^{1413305111341} is an apocalyptic number.

It is an amenable number.

1413305111341 is a deficient number, since it is larger than the sum of its proper divisors (1293052431).

1413305111341 is a wasteful number, since it uses less digits than its factorization.

1413305111341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1293052430.

The product of its (nonzero) digits is 2160, while the sum is 28.

The spelling of 1413305111341 in words is "one trillion, four hundred thirteen billion, three hundred five million, one hundred eleven thousand, three hundred forty-one".