14134014113 has 8 divisors (see below), whose sum is σ = 14637979200. Its totient is φ = 13631154768.

The previous prime is 14134014077. The next prime is 14134014127. The reversal of 14134014113 is 31141043141.

14134014113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14134014113 - 2⁸ = 14134013857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14134014133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 250373 + ... + 301586.

It is an arithmetic number, because the mean of its divisors is an integer number (1829747400).

Almost surely, 2^14134014113 is an apocalyptic number.

It is an amenable number.

14134014113 is a deficient number, since it is larger than the sum of its proper divisors (503965087).

14134014113 is an equidigital number, since it uses as much as digits as its factorization.

14134014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 552871.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14134014113 its reverse (31141043141), we get a palindrome (45275057254).

The spelling of 14134014113 in words is "fourteen billion, one hundred thirty-four million, fourteen thousand, one hundred thirteen".