141340410331053 has 4 divisors (see below), whose sum is σ = 188453880441408. Its totient is φ = 94226940220700.

The previous prime is 141340410331051. The next prime is 141340410331069. The reversal of 141340410331053 is 350133014043141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141340410331053 - 2¹ = 141340410331051 is a prime.

It is a super-2 number, since 2×141340410331053² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141340410331051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23556735055173 + ... + 23556735055178.

It is an arithmetic number, because the mean of its divisors is an integer number (47113470110352).

Almost surely, 2^{141340410331053} is an apocalyptic number.

It is an amenable number.

141340410331053 is a deficient number, since it is larger than the sum of its proper divisors (47113470110355).

141340410331053 is an equidigital number, since it uses as much as digits as its factorization.

141340410331053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47113470110354.

The product of its (nonzero) digits is 25920, while the sum is 33.

Adding to 141340410331053 its reverse (350133014043141), we get a palindrome (491473424374194).

The spelling of 141340410331053 in words is "one hundred forty-one trillion, three hundred forty billion, four hundred ten million, three hundred thirty-one thousand, fifty-three".