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14134121011010 = 25711137918479677
BaseRepresentation
bin1100110110101101101101…
…0000110001011101000010
31212001012122012021020201202
43031223123100301131002
53323033134434323020
650021043041501202
72656104460213220
oct315533320613502
955035565236652
1014134121011010
11455a279920340
121703354641802
137b6ac3839320
1436c148d8bb10
151979da93be75
hexcdadb431742

14134121011010 has 256 divisors, whose sum is σ = 34613805219840. Its totient is φ = 4012496317440.

The previous prime is 14134121011009. The next prime is 14134121011061. The reversal of 14134121011010 is 1011012143141.

14134121011010 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1460584292 + ... + 1460593968.

It is an arithmetic number, because the mean of its divisors is an integer number (135210176640).

Almost surely, 214134121011010 is an apocalyptic number.

14134121011010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14134121011010 is an abundant number, since it is smaller than the sum of its proper divisors (20479684208830).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14134121011010 is a wasteful number, since it uses less digits than its factorization.

14134121011010 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11641.

The product of its (nonzero) digits is 96, while the sum is 20.

Adding to 14134121011010 its reverse (1011012143141), we get a palindrome (15145133154151).

The spelling of 14134121011010 in words is "fourteen trillion, one hundred thirty-four billion, one hundred twenty-one million, eleven thousand, ten".