Base | Representation |
---|---|
bin | 100000001000110010011100… |
… | …100100010110100100110000 |
3 | 200112110002212220212000001122 |
4 | 200020302130210112210300 |
5 | 122011214202100131422 |
6 | 1220335203030321412 |
7 | 41525402625613211 |
oct | 4010623444264460 |
9 | 615402786760048 |
10 | 141341410552112 |
11 | 41043612548121 |
12 | 13a28ab44b9268 |
13 | 60b358cb91ac4 |
14 | 26c8d64501408 |
15 | 1151933b74d42 |
hex | 808c9c916930 |
141341410552112 has 20 divisors (see below), whose sum is σ = 273868683324096. Its totient is φ = 70665621307200.
The previous prime is 141341410552099. The next prime is 141341410552163. The reversal of 141341410552112 is 211255014143141.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 317518688 + ... + 317963519.
Almost surely, 2141341410552112 is an apocalyptic number.
It is an amenable number.
141341410552112 is a deficient number, since it is larger than the sum of its proper divisors (132527272771984).
141341410552112 is a wasteful number, since it uses less digits than its factorization.
141341410552112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 635496116 (or 635496110 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 35.
Adding to 141341410552112 its reverse (211255014143141), we get a palindrome (352596424695253).
The spelling of 141341410552112 in words is "one hundred forty-one trillion, three hundred forty-one billion, four hundred ten million, five hundred fifty-two thousand, one hundred twelve".
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