Base | Representation |
---|---|
bin | 11010010100111100… |
… | …11101110000110111 |
3 | 1100111001101000121012 |
4 | 31022132131300313 |
5 | 212421401331403 |
6 | 10254313142435 |
7 | 1010156302253 |
oct | 151236356067 |
9 | 40431330535 |
10 | 14134402103 |
11 | 5aa3557558 |
12 | 28a56baa1b |
13 | 1443409253 |
14 | 9812a1263 |
15 | 57ad30ed8 |
hex | 34a79dc37 |
14134402103 has 2 divisors, whose sum is σ = 14134402104. Its totient is φ = 14134402102.
The previous prime is 14134402063. The next prime is 14134402147. The reversal of 14134402103 is 30120443141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14134402103 - 210 = 14134401079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14134402193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7067201051 + 7067201052.
It is an arithmetic number, because the mean of its divisors is an integer number (7067201052).
Almost surely, 214134402103 is an apocalyptic number.
14134402103 is a deficient number, since it is larger than the sum of its proper divisors (1).
14134402103 is an equidigital number, since it uses as much as digits as its factorization.
14134402103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14134402103 its reverse (30120443141), we get a palindrome (44254845244).
The spelling of 14134402103 in words is "fourteen billion, one hundred thirty-four million, four hundred two thousand, one hundred three".
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