1413462643141 has 4 divisors (see below), whose sum is σ = 1415428516800. Its totient is φ = 1411496769484.

The previous prime is 1413462643111. The next prime is 1413462643157.

1413462643141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1413462643141 - 2¹¹ = 1413462641093 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1413462643094 and 1413462643103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413462643111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 982935751 + ... + 982937188.

It is an arithmetic number, because the mean of its divisors is an integer number (353857129200).

Almost surely, 2^{1413462643141} is an apocalyptic number.

It is an amenable number.

1413462643141 is a deficient number, since it is larger than the sum of its proper divisors (1965873659).

1413462643141 is an equidigital number, since it uses as much as digits as its factorization.

1413462643141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1965873658.

The product of its digits is 165888, while the sum is 40.

The spelling of 1413462643141 in words is "one trillion, four hundred thirteen billion, four hundred sixty-two million, six hundred forty-three thousand, one hundred forty-one".