Search a number
-
+
14135261141 is a prime number
BaseRepresentation
bin11010010101000011…
…01111011111010101
31100111002222122222102
431022201233133111
5212422111324031
610254343411445
71010166510611
oct151241573725
940432878872
1014135261141
115aa3a93a01
1228a5a53b85
13144364a261
14981446341
1557ae507cb
hex34a86f7d5

14135261141 has 2 divisors, whose sum is σ = 14135261142. Its totient is φ = 14135261140.

The previous prime is 14135261069. The next prime is 14135261143. The reversal of 14135261141 is 14116253141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8663700241 + 5471560900 = 93079^2 + 73970^2 .

It is an emirp because it is prime and its reverse (14116253141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14135261141 - 222 = 14131066837 is a prime.

Together with 14135261143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14135261143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7067630570 + 7067630571.

It is an arithmetic number, because the mean of its divisors is an integer number (7067630571).

Almost surely, 214135261141 is an apocalyptic number.

It is an amenable number.

14135261141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14135261141 is an equidigital number, since it uses as much as digits as its factorization.

14135261141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2880, while the sum is 29.

The spelling of 14135261141 in words is "fourteen billion, one hundred thirty-five million, two hundred sixty-one thousand, one hundred forty-one".