Base | Representation |
---|---|
bin | 10100100100111010111… |
… | …000110110010001111111 |
3 | 12000011212100002111101021 |
4 | 110210322320312101333 |
5 | 141131414222040221 |
6 | 3001333013525011 |
7 | 204106015365163 |
oct | 24447270662177 |
9 | 5004770074337 |
10 | 1414032221311 |
11 | 4a5762363906 |
12 | 1aa070643767 |
13 | a345bab7ac8 |
14 | 4c6220acca3 |
15 | 26bb000a041 |
hex | 1493ae3647f |
1414032221311 has 2 divisors, whose sum is σ = 1414032221312. Its totient is φ = 1414032221310.
The previous prime is 1414032221297. The next prime is 1414032221339. The reversal of 1414032221311 is 1131222304141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1414032221311 - 25 = 1414032221279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1414039221311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707016110655 + 707016110656.
It is an arithmetic number, because the mean of its divisors is an integer number (707016110656).
Almost surely, 21414032221311 is an apocalyptic number.
1414032221311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414032221311 is an equidigital number, since it uses as much as digits as its factorization.
1414032221311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1414032221311 its reverse (1131222304141), we get a palindrome (2545254525452).
The spelling of 1414032221311 in words is "one trillion, four hundred fourteen billion, thirty-two million, two hundred twenty-one thousand, three hundred eleven".
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