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1414067574113 is a prime number
BaseRepresentation
bin10100100100111100111…
…111101101010101100001
312000011221210121121022022
4110210330333231111201
5141132002244332423
63001340315351225
7204106625026445
oct24447477552541
95004853547268
101414067574113
114a578030a9a7
121aa080452515
13a346621531c
144c626a72825
1526bb318edc8
hex1493cfed561

1414067574113 has 2 divisors, whose sum is σ = 1414067574114. Its totient is φ = 1414067574112.

The previous prime is 1414067574077. The next prime is 1414067574119. The reversal of 1414067574113 is 3114757604141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1010171735329 + 403895838784 = 1005073^2 + 635528^2 .

It is an emirp because it is prime and its reverse (3114757604141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1414067574113 - 220 = 1414066525537 is a prime.

It is not a weakly prime, because it can be changed into another prime (1414067574119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707033787056 + 707033787057.

It is an arithmetic number, because the mean of its divisors is an integer number (707033787057).

Almost surely, 21414067574113 is an apocalyptic number.

It is an amenable number.

1414067574113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414067574113 is an equidigital number, since it uses as much as digits as its factorization.

1414067574113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 282240, while the sum is 44.

The spelling of 1414067574113 in words is "one trillion, four hundred fourteen billion, sixty-seven million, five hundred seventy-four thousand, one hundred thirteen".