Base | Representation |
---|---|
bin | 1100110111001101000101… |
… | …0000100111010101101111 |
3 | 1212002000101010222022210100 |
4 | 3031303101100213111233 |
5 | 3323202412020211030 |
6 | 50024554501042143 |
7 | 2656523255106654 |
oct | 315632120472557 |
9 | 55060333868710 |
10 | 14142543132015 |
11 | 45629009a2521 |
12 | 1704b050b6353 |
13 | 7b783666768c |
14 | 36c707737c2b |
15 | 197d3001a360 |
hex | cdcd142756f |
14142543132015 has 24 divisors (see below), whose sum is σ = 24520000029408. Its totient is φ = 7540763947200.
The previous prime is 14142543132007. The next prime is 14142543132037. The reversal of 14142543132015 is 51023134524141.
14142543132015 is a `hidden beast` number, since 1 + 4 + 14 + 2 + 5 + 431 + 3 + 201 + 5 = 666.
It is not a de Polignac number, because 14142543132015 - 23 = 14142543132007 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39941011 + ... + 40293540.
It is an arithmetic number, because the mean of its divisors is an integer number (1021666667892).
Almost surely, 214142543132015 is an apocalyptic number.
14142543132015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14142543132015 is a deficient number, since it is larger than the sum of its proper divisors (10377456897393).
14142543132015 is a wasteful number, since it uses less digits than its factorization.
14142543132015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80238479 (or 80238476 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 14142543132015 its reverse (51023134524141), we get a palindrome (65165677656156).
The spelling of 14142543132015 in words is "fourteen trillion, one hundred forty-two billion, five hundred forty-three million, one hundred thirty-two thousand, fifteen".
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