Base | Representation |
---|---|
bin | 11010010101111111… |
… | …01100000100010001 |
3 | 1100111122202111120021 |
4 | 31022333230010101 |
5 | 212431114031231 |
6 | 10255223543441 |
7 | 1010323315024 |
oct | 151277540421 |
9 | 40448674507 |
10 | 14143111441 |
11 | 5aa8465a58 |
12 | 28a85bab81 |
13 | 14451684c4 |
14 | 9824cb1bb |
15 | 57b9a1811 |
hex | 34afec111 |
14143111441 has 2 divisors, whose sum is σ = 14143111442. Its totient is φ = 14143111440.
The previous prime is 14143111421. The next prime is 14143111487. The reversal of 14143111441 is 14411134141.
It is a happy number.
14143111441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12299697216 + 1843414225 = 110904^2 + 42935^2 .
It is a cyclic number.
It is not a de Polignac number, because 14143111441 - 27 = 14143111313 is a prime.
It is not a weakly prime, because it can be changed into another prime (14143111421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7071555720 + 7071555721.
It is an arithmetic number, because the mean of its divisors is an integer number (7071555721).
Almost surely, 214143111441 is an apocalyptic number.
It is an amenable number.
14143111441 is a deficient number, since it is larger than the sum of its proper divisors (1).
14143111441 is an equidigital number, since it uses as much as digits as its factorization.
14143111441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 768, while the sum is 25.
Adding to 14143111441 its reverse (14411134141), we get a palindrome (28554245582).
The spelling of 14143111441 in words is "fourteen billion, one hundred forty-three million, one hundred eleven thousand, four hundred forty-one".
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