141432401300111 has 8 divisors (see below), whose sum is σ = 144477179850240. Its totient is φ = 138401557664032.

The previous prime is 141432401300011. The next prime is 141432401300137. The reversal of 141432401300111 is 111003104234141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141432401300111 is a prime.

It is a super-2 number, since 2×141432401300111² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141432401300011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3483707996 + ... + 3483748593.

It is an arithmetic number, because the mean of its divisors is an integer number (18059647481280).

Almost surely, 2^{141432401300111} is an apocalyptic number.

141432401300111 is a deficient number, since it is larger than the sum of its proper divisors (3044778550129).

141432401300111 is an equidigital number, since it uses as much as digits as its factorization.

141432401300111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6967457025.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 141432401300111 its reverse (111003104234141), we get a palindrome (252435505534252).

The spelling of 141432401300111 in words is "one hundred forty-one trillion, four hundred thirty-two billion, four hundred one million, three hundred thousand, one hundred eleven".