Base | Representation |
---|---|
bin | 1100110111010000101010… |
… | …0011010010111100110011 |
3 | 1212002002212010122021021222 |
4 | 3031310022203102330303 |
5 | 3323211344102034142 |
6 | 50025234114535255 |
7 | 2656556136134024 |
oct | 315641243227463 |
9 | 55062763567258 |
10 | 14143504330547 |
11 | 4563254524179 |
12 | 1705132b9752b |
13 | 7b795a83a6c7 |
14 | 36c799264c4b |
15 | 197d895d4bd2 |
hex | cdd0a8d2f33 |
14143504330547 has 2 divisors, whose sum is σ = 14143504330548. Its totient is φ = 14143504330546.
The previous prime is 14143504330499. The next prime is 14143504330559. The reversal of 14143504330547 is 74503340534141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14143504330547 - 212 = 14143504326451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14143504330498 and 14143504330507.
It is not a weakly prime, because it can be changed into another prime (14143504335547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7071752165273 + 7071752165274.
It is an arithmetic number, because the mean of its divisors is an integer number (7071752165274).
Almost surely, 214143504330547 is an apocalyptic number.
14143504330547 is a deficient number, since it is larger than the sum of its proper divisors (1).
14143504330547 is an equidigital number, since it uses as much as digits as its factorization.
14143504330547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1209600, while the sum is 44.
Adding to 14143504330547 its reverse (74503340534141), we get a palindrome (88646844864688).
The spelling of 14143504330547 in words is "fourteen trillion, one hundred forty-three billion, five hundred four million, three hundred thirty thousand, five hundred forty-seven".
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