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1414430556403 is a prime number
BaseRepresentation
bin10100100101010010101…
…000011000000011110011
312000012220002122000101211
4110211102220120003303
5141133223210301103
63001440323340551
7204121623234034
oct24452250300363
95005802560354
101414430556403
114a59471a1967
121aa161b21757
13a34c3495647
144c65cd5ca8b
1526bd4e9036d
hex14952a180f3

1414430556403 has 2 divisors, whose sum is σ = 1414430556404. Its totient is φ = 1414430556402.

The previous prime is 1414430556401. The next prime is 1414430556439. The reversal of 1414430556403 is 3046550344141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1414430556403 - 21 = 1414430556401 is a prime.

It is a super-2 number, since 2×14144305564032 (a number of 25 digits) contains 22 as substring.

Together with 1414430556401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1414430556401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707215278201 + 707215278202.

It is an arithmetic number, because the mean of its divisors is an integer number (707215278202).

Almost surely, 21414430556403 is an apocalyptic number.

1414430556403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414430556403 is an equidigital number, since it uses as much as digits as its factorization.

1414430556403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 40.

The spelling of 1414430556403 in words is "one trillion, four hundred fourteen billion, four hundred thirty million, five hundred fifty-six thousand, four hundred three".