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1415144434343 is a prime number
BaseRepresentation
bin10100100101111101001…
…011100110101010100111
312000021201211220202211112
4110211331023212222213
5141141203433344333
63002035224255235
7204145412135603
oct24457513465247
95007654822745
101415144434343
114a618315aa32
121aa32101151b
13a35a8353723
144c6c9aaa503
1526c279a4948
hex1497d2e6aa7

1415144434343 has 2 divisors, whose sum is σ = 1415144434344. Its totient is φ = 1415144434342.

The previous prime is 1415144434337. The next prime is 1415144434367. The reversal of 1415144434343 is 3434344415141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1415144434343 - 232 = 1410849467047 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1415144434343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1415144434373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707572217171 + 707572217172.

It is an arithmetic number, because the mean of its divisors is an integer number (707572217172).

Almost surely, 21415144434343 is an apocalyptic number.

1415144434343 is a deficient number, since it is larger than the sum of its proper divisors (1).

1415144434343 is an equidigital number, since it uses as much as digits as its factorization.

1415144434343 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 552960, while the sum is 41.

Adding to 1415144434343 its reverse (3434344415141), we get a palindrome (4849488849484).

The spelling of 1415144434343 in words is "one trillion, four hundred fifteen billion, one hundred forty-four million, four hundred thirty-four thousand, three hundred forty-three".