14153670068453 has 4 divisors (see below), whose sum is σ = 14482825186368. Its totient is φ = 13824514950540.

The previous prime is 14153670068411. The next prime is 14153670068467. The reversal of 14153670068453 is 35486007635141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14153670068453 - 2⁶ = 14153670068389 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14153670068395 and 14153670068404.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14153670058453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164577558893 + ... + 164577558978.

It is an arithmetic number, because the mean of its divisors is an integer number (3620706296592).

Almost surely, 2^{14153670068453} is an apocalyptic number.

It is an amenable number.

14153670068453 is a deficient number, since it is larger than the sum of its proper divisors (329155117915).

14153670068453 is an equidigital number, since it uses as much as digits as its factorization.

14153670068453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 329155117914.

The product of its (nonzero) digits is 7257600, while the sum is 53.

The spelling of 14153670068453 in words is "fourteen trillion, one hundred fifty-three billion, six hundred seventy million, sixty-eight thousand, four hundred fifty-three".