141647062421 has 2 divisors, whose sum is σ = 141647062422. Its totient is φ = 141647062420.

The previous prime is 141647062391. The next prime is 141647062423. The reversal of 141647062421 is 124260746141.

141647062421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129261820900 + 12385241521 = 359530^2 + 111289^2 .

It is a cyclic number.

It is not a de Polignac number, because 141647062421 - 2⁶ = 141647062357 is a prime.

It is a super-3 number, since 3×141647062421³ (a number of 34 digits) contains 333 as substring.

Together with 141647062423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141647062423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70823531210 + 70823531211.

It is an arithmetic number, because the mean of its divisors is an integer number (70823531211).

Almost surely, 2^141647062421 is an apocalyptic number.

It is an amenable number.

141647062421 is a deficient number, since it is larger than the sum of its proper divisors (1).

141647062421 is an equidigital number, since it uses as much as digits as its factorization.

141647062421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64512, while the sum is 38.

The spelling of 141647062421 in words is "one hundred forty-one billion, six hundred forty-seven million, sixty-two thousand, four hundred twenty-one".