Base | Representation |
---|---|
bin | 11010011001100101… |
… | …01110101111010011 |
3 | 1100120202111122212221 |
4 | 31030302232233103 |
5 | 213011324101242 |
6 | 10302222201511 |
7 | 1011140540545 |
oct | 151462565723 |
9 | 40522448787 |
10 | 14173268947 |
11 | 6013493812 |
12 | 28b6723297 |
13 | 144b497096 |
14 | 9864db695 |
15 | 57e45c167 |
hex | 34ccaebd3 |
14173268947 has 2 divisors, whose sum is σ = 14173268948. Its totient is φ = 14173268946.
The previous prime is 14173268933. The next prime is 14173268999. The reversal of 14173268947 is 74986237141.
It is a happy number.
It is an a-pointer prime, because the next prime (14173268999) can be obtained adding 14173268947 to its sum of digits (52).
It is a weak prime.
It is an emirp because it is prime and its reverse (74986237141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14173268947 - 215 = 14173236179 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14173268894 and 14173268903.
It is not a weakly prime, because it can be changed into another prime (14173268047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7086634473 + 7086634474.
It is an arithmetic number, because the mean of its divisors is an integer number (7086634474).
Almost surely, 214173268947 is an apocalyptic number.
14173268947 is a deficient number, since it is larger than the sum of its proper divisors (1).
14173268947 is an equidigital number, since it uses as much as digits as its factorization.
14173268947 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2032128, while the sum is 52.
The spelling of 14173268947 in words is "fourteen billion, one hundred seventy-three million, two hundred sixty-eight thousand, nine hundred forty-seven".
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