Base | Representation |
---|---|
bin | 11010011010111111… |
… | …10110010011110111 |
3 | 1100121120202120011012 |
4 | 31031133312103313 |
5 | 213022341041224 |
6 | 10303323502435 |
7 | 1011343221203 |
oct | 151537662367 |
9 | 40546676135 |
10 | 14185096439 |
11 | 601a1319a8 |
12 | 28ba687a1b |
13 | 1450a786b7 |
14 | 987cd9b03 |
15 | 5804e680e |
hex | 34d7f64f7 |
14185096439 has 2 divisors, whose sum is σ = 14185096440. Its totient is φ = 14185096438.
The previous prime is 14185096423. The next prime is 14185096447. The reversal of 14185096439 is 93469058141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14185096439 - 24 = 14185096423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14185096459) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7092548219 + 7092548220.
It is an arithmetic number, because the mean of its divisors is an integer number (7092548220).
Almost surely, 214185096439 is an apocalyptic number.
14185096439 is a deficient number, since it is larger than the sum of its proper divisors (1).
14185096439 is an equidigital number, since it uses as much as digits as its factorization.
14185096439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 933120, while the sum is 50.
The spelling of 14185096439 in words is "fourteen billion, one hundred eighty-five million, ninety-six thousand, four hundred thirty-nine".
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