Base | Representation |
---|---|
bin | 10100101001101001100… |
… | …110101101101110110111 |
3 | 12000122222021122100210221 |
4 | 110221221212231232313 |
5 | 141222314401323101 |
6 | 3003533000555211 |
7 | 204345615111466 |
oct | 24515146555667 |
9 | 5018867570727 |
10 | 1419110964151 |
11 | 4a7929163541 |
12 | 1ab049482b07 |
13 | a3a8b05679a |
14 | 4c9847ca9dd |
15 | 26daad17aa1 |
hex | 14a699adbb7 |
1419110964151 has 2 divisors, whose sum is σ = 1419110964152. Its totient is φ = 1419110964150.
The previous prime is 1419110964149. The next prime is 1419110964239. The reversal of 1419110964151 is 1514690119141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1419110964151 - 21 = 1419110964149 is a prime.
Together with 1419110964149, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1419110964098 and 1419110964107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1419110964101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 709555482075 + 709555482076.
It is an arithmetic number, because the mean of its divisors is an integer number (709555482076).
Almost surely, 21419110964151 is an apocalyptic number.
1419110964151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1419110964151 is an equidigital number, since it uses as much as digits as its factorization.
1419110964151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 43.
The spelling of 1419110964151 in words is "one trillion, four hundred nineteen billion, one hundred ten million, nine hundred sixty-four thousand, one hundred fifty-one".
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