142004000311 has 2 divisors, whose sum is σ = 142004000312. Its totient is φ = 142004000310.

The previous prime is 142004000309. The next prime is 142004000339. The reversal of 142004000311 is 113000400241.

It is a weak prime.

It is an emirp because it is prime and its reverse (113000400241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142004000311 - 2¹ = 142004000309 is a prime.

It is a super-2 number, since 2×142004000311² (a number of 23 digits) contains 22 as substring.

Together with 142004000309, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142004000711) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71002000155 + 71002000156.

It is an arithmetic number, because the mean of its divisors is an integer number (71002000156).

Almost surely, 2^142004000311 is an apocalyptic number.

142004000311 is a deficient number, since it is larger than the sum of its proper divisors (1).

142004000311 is an equidigital number, since it uses as much as digits as its factorization.

142004000311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 142004000311 its reverse (113000400241), we get a palindrome (255004400552).

The spelling of 142004000311 in words is "one hundred forty-two billion, four million, three hundred eleven", and thus it is an aban number.