Base | Representation |
---|---|
bin | 1100111010100101000101… |
… | …0000101100001110001111 |
3 | 1212021120001000111002122002 |
4 | 3032221101100230032033 |
5 | 3330130133423214021 |
6 | 50111344202142515 |
7 | 2663645152461413 |
oct | 316512120541617 |
9 | 55246030432562 |
10 | 14200525210511 |
11 | 4585455302262 |
12 | 17141a71b1a3b |
13 | 7c0147014173 |
14 | 3714481c8d43 |
15 | 1995c551a50b |
hex | cea5142c38f |
14200525210511 has 4 divisors (see below), whose sum is σ = 15035850222912. Its totient is φ = 13365200198112.
The previous prime is 14200525210463. The next prime is 14200525210541. The reversal of 14200525210511 is 11501252500241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14200525210511 - 26 = 14200525210447 is a prime.
It is a super-2 number, since 2×142005252105112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14200525210541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 417662506175 + ... + 417662506208.
It is an arithmetic number, because the mean of its divisors is an integer number (3758962555728).
Almost surely, 214200525210511 is an apocalyptic number.
14200525210511 is a deficient number, since it is larger than the sum of its proper divisors (835325012401).
14200525210511 is an equidigital number, since it uses as much as digits as its factorization.
14200525210511 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 835325012400.
The product of its (nonzero) digits is 4000, while the sum is 29.
Adding to 14200525210511 its reverse (11501252500241), we get a palindrome (25701777710752).
The spelling of 14200525210511 in words is "fourteen trillion, two hundred billion, five hundred twenty-five million, two hundred ten thousand, five hundred eleven".
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