142012111 has 2 divisors, whose sum is σ = 142012112. Its totient is φ = 142012110.

The previous prime is 142012063. The next prime is 142012121. The reversal of 142012111 is 111210241.

It is a strong prime.

It is an emirp because it is prime and its reverse (111210241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142012111 - 2⁷ = 142011983 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 142012091 and 142012100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142012121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71006055 + 71006056.

It is an arithmetic number, because the mean of its divisors is an integer number (71006056).

Almost surely, 2^142012111 is an apocalyptic number.

142012111 is a deficient number, since it is larger than the sum of its proper divisors (1).

142012111 is an equidigital number, since it uses as much as digits as its factorization.

142012111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 13.

The square root of 142012111 is about 11916.8834432497. The cubic root of 142012111 is about 521.7251762106.

Adding to 142012111 its reverse (111210241), we get a palindrome (253222352).

It can be divided in two parts, 1420 and 12111, that added together give a palindrome (13531).

The spelling of 142012111 in words is "one hundred forty-two million, twelve thousand, one hundred eleven".