Base | Representation |
---|---|
bin | 1100111010101000011101… |
… | …0100101101001001101011 |
3 | 1212021122101020012120222010 |
4 | 3032222013110231021223 |
5 | 3330134013122420210 |
6 | 50112014202531003 |
7 | 2664006505154511 |
oct | 316520724551153 |
9 | 55248336176863 |
10 | 14201432232555 |
11 | 45858802a0357 |
12 | 17143bab06a63 |
13 | 7c025cbc8ab9 |
14 | 3714d28524b1 |
15 | 199629e82920 |
hex | cea8752d26b |
14201432232555 has 8 divisors (see below), whose sum is σ = 22722291572112. Its totient is φ = 7574097190688.
The previous prime is 14201432232479. The next prime is 14201432232569. The reversal of 14201432232555 is 55523223410241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14201432232555 - 214 = 14201432216171 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 473381074404 + ... + 473381074433.
It is an arithmetic number, because the mean of its divisors is an integer number (2840286446514).
Almost surely, 214201432232555 is an apocalyptic number.
14201432232555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14201432232555 is a deficient number, since it is larger than the sum of its proper divisors (8520859339557).
14201432232555 is an equidigital number, since it uses as much as digits as its factorization.
14201432232555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 946762148845.
The product of its (nonzero) digits is 288000, while the sum is 39.
Adding to 14201432232555 its reverse (55523223410241), we get a palindrome (69724655642796).
The spelling of 14201432232555 in words is "fourteen trillion, two hundred one billion, four hundred thirty-two million, two hundred thirty-two thousand, five hundred fifty-five".
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