14201713152000 has 1664 divisors, whose sum is σ = 58039334346240. Its totient is φ = 3439853568000.

The previous prime is 14201713151903. The next prime is 14201713152023. The reversal of 14201713152000 is 25131710241.

14201713152000 is a `hidden beast` number, since 1 + 4 + 2 + 0 + 1 + 7 + 131 + 520 + 0 + 0 = 666.

It is a super-3 number, since 3×14201713152000³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 12317183424 + ... + 12317184576.

It is an arithmetic number, because the mean of its divisors is an integer number (34879407660).

Almost surely, 2^{14201713152000} is an apocalyptic number.

14201713152000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14201713152000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29019667173120).

14201713152000 is an abundant number, since it is smaller than the sum of its proper divisors (43837621194240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14201713152000 is an frugal number, since it uses more digits than its factorization.

14201713152000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1224 (or 1174 counting only the distinct ones).

The product of its (nonzero) digits is 1680, while the sum is 27.

Adding to 14201713152000 its reverse (25131710241), we get a palindrome (14226844862241).

The spelling of 14201713152000 in words is "fourteen trillion, two hundred one billion, seven hundred thirteen million, one hundred fifty-two thousand".