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1420200243311 = 17659132795531
BaseRepresentation
bin10100101010101010100…
…001111111000001101111
312000202210012022110220112
4110222222201333001233
5141232032230241221
63004233032010235
7204414612613463
oct24525241770157
95022705273815
101420200243311
114a8338016053
121ab2b223097b
13a3c02922775
144ca493384a3
1526e2178215b
hex14aaa87f06f

1420200243311 has 16 divisors (see below), whose sum is σ = 1507173972480. Its totient is φ = 1333611027840.

The previous prime is 1420200243271. The next prime is 1420200243317. The reversal of 1420200243311 is 1133420020241.

It is not a de Polignac number, because 1420200243311 - 222 = 1420196049007 is a prime.

It is a super-2 number, since 2×14202002433112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1420200243317) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14818616 + ... + 14914146.

It is an arithmetic number, because the mean of its divisors is an integer number (94198373280).

Almost surely, 21420200243311 is an apocalyptic number.

1420200243311 is a deficient number, since it is larger than the sum of its proper divisors (86973729169).

1420200243311 is a wasteful number, since it uses less digits than its factorization.

1420200243311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97534.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1420200243311 its reverse (1133420020241), we get a palindrome (2553620263552).

The spelling of 1420200243311 in words is "one trillion, four hundred twenty billion, two hundred million, two hundred forty-three thousand, three hundred eleven".

Divisors: 1 17 659 1327 11203 22559 95531 874493 1624027 14866381 62954929 126769637 1070233793 2155083829 83541190783 1420200243311